Leetcode: Clone Graph
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.
OJ’s undirected graph serialization:
Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
-
First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
-
Second node is labeled as 1. Connect node 1 to node 2.
-
Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/
这题的做法还是参考Copy List with Random Pointer,首先为旧图中的每一个node生成一个新node,再建立一条旧图node指向相应新node的边,再把旧图中的每一条边“平移”到新图中即可。
代码:
/**
* Definition for undirected graph.
* struct UndirectedGraphNode {
* int label;
* vector<UndirectedGraphNode *> neighbors;
* UndirectedGraphNode(int x) : label(x) {};
* };
*/
class Solution {
public:
UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
if(node == NULL) return NULL;
unordered_set<UndirectedGraphNode *> table;
vector<UndirectedGraphNode *> old;
table.insert(node);
old.push_back(node);
for(int i = 0; i < old.size(); ++i){
for(int j = 0; j < old[i] -> neighbors.size(); ++j){
if(table.find(old[i] -> neighbors[j]) == table.end()){
table.insert(old[i] -> neighbors[j]);
old.push_back(old[i] -> neighbors[j]);
}
}
}
int n = old.size();
for(int i = 0; i < n; ++i){
UndirectedGraphNode *newnode = new UndirectedGraphNode(old[i] -> label);
old[i] -> neighbors.push_back(newnode);
}
for(int i = 0; i < n; ++i){
int edgenum = old[i] -> neighbors.size() - 1;
UndirectedGraphNode *newnode = old[i] -> neighbors[edgenum];
for(int j = 0; j < edgenum; ++j){
newnode -> neighbors.push_back(old[i] -> neighbors[j] -> neighbors[old[i] -> neighbors[j] -> neighbors.size() - 1]);
}
}
UndirectedGraphNode *ret = old[0] -> neighbors[old[0] -> neighbors.size() - 1];
for(int i = 0; i < n; ++i) old[i] -> neighbors.pop_back();
return ret;
}
};